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Calculus Help ASAP

A photo of thecookiemonster thecookiemonster
Hi smart people of the business section of this forum:

I missed a couple calculus classes, and I am way behind, and struggling with the homework atm (long weekend didn't help). I was hoping some of you could help me out so I can gain a bit of an understanding before i go in for extra help tomorrow.

They're really, really easy questions, I am just drawing a blank.

Find dy/dx for each function:

y=-3log3(x+2) <-- the three after the log is subscript btw

Differentiate:

y=3^x log3x <-- again 3 after log is subscript

y=3^lnx

.......................

If anyone can help, mucho thanks will go out to you!!
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A photo of thecookiemonster thecookiemonster
20 views and no one can help me? Come on, I really need some help. I will give everyone who helps a rabbit- :albino: , and if no one helps, I may have to go all :rambo: on you
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A photo of immaculatedx immaculatedx
I`ll give you some helpful hints:

Derivative of y=loga(g(x)) is y'= g'(x) / (g(x)*lna)
The derivative of y = lnx is y' = 1/x
For the exponent questions, use the chain rule, if f(x) = g(h(x)), then f'(x) = g'((h(x))*h'(x)
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A photo of thecookiemonster thecookiemonster

@immaculatedx wrote
I`ll give you some helpful hints:

Derivative of y=loga(g(x)) is y'= g'(x) / (g(x)*lna)
The derivative of y = lnx is y' = 1/x
For the exponent questions, use the chain rule, if f(x) = g(h(x)), then f'(x) = g'((h(x))*h'(x)


Thanks
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A photo of immaculatedx immaculatedx

@thecookiemonster wrote

@immaculatedx wrote
I`ll give you some helpful hints:

Derivative of y=loga(g(x)) is y'= g'(x) / (g(x)*lna)
The derivative of y = lnx is y' = 1/x
For the exponent questions, use the chain rule, if f(x) = g(h(x)), then f'(x) = g'((h(x))*h'(x)


Thanks



You'll need the product rule as well for question 2 I believe.
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